Oh , thanks a lot , will try very soon, indeed, wonderful ;

thanks a lot,
Opa Peter


Op dinsdag 11 mei 2021 om 22:55:56 UTC+2 schreef [email protected]:

> The sympy.solvers.solveset.linear_eq_to_matrix is probably what you are 
> needing:
>
> ```python
>     >>> eqns = [c*x + z - 1 - c, y + z, x - y]
>     >>> A, b = linear_eq_to_matrix(eqns, [x, y, z])
>     >>> A
>     Matrix([
>     [c,  0, 1],
>     [0,  1, 1],
>     [1, -1, 0]])
>     >>> b
>     Matrix([
>     [c + 1],
>     [    0],
>     [    0]])
> ```
>
> On Tuesday, May 11, 2021 at 12:54:49 PM UTC-5 [email protected] wrote:
>
>> Got adain interested in a book LINEAR ALGEBRA  with APLICATIONS, very 
>> nice book, very early there are exercises to show the corresponding matrix 
>> of coeffients. Trivial, if one types by reading the ckeeficients to bild 
>> the riws Matrix needs. But now my question : How to generate thebmatrix by 
>> a def ....
>> ok lhs and rhs of an Eq is easy, using args too .  But what dimyoundo if 
>> there are equations with differen numbers of say x_i. Missing unknows have 
>> to create an 0 at the needed row.index. 
>> I translated an equation (lhs) with srepr with regular expression , 
>> replacing  Symbol ('x1) to 1 etc .
>>
>> Questions , how would you trans form e.g  x1 + x3 - 2*x5   To
>> 1 0 1 0 -2 ?
>>
>>  Ok, I extract x1 x3 and x5 ==>!knowing now x2 and x4 is missing, knowing 
>> the 0 at  index 1 and 3 (zero order of Python) ... 
>>   
>> Have to learn to give code examples here ... Pictutes ? 
>> Newbie in this groep
>>
>> Ideas and help very much apteciated  😉 , by the way i am an 祖父 is 
>> grandpa 
>>
>>

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