You should be able to obtain a parametric Groebner basis to represent
the solutions of this system. Whether that leads to an explicit
solution in radicals is hard to say without trying.

I would demonstrate how to do this but the code for putting together
the equations is incomplete.

On Fri, 5 Aug 2022 at 14:01, Chris Smith <[email protected]> wrote:
>
> If you remove the radicals (`sympy.solvers.solvers.unrad(eq1)`) and replace 
> `Q1` and `Q2` with `x` and `y` and `Q_dp_1` with a and `s1` with `b` you will 
> get an expression that is of degree 4 in every variable and can be split into 
> a term with `a` and `b` and a term with only `b` -- both with `x` and `y`.
>
> u1 = a*(a**3 - 4*a**2*y*(2 - b) - 2*a*y**2*(-3*b**2 + 8*b - 8) - 4*b**3*x**3 
> + 2*b**2*(-x**2*(-3*a + 2*y*(b - 2)) + 2*y**3*(b - 2)) - 4*b*x*(a**2 + a*y*(b 
> - 2) + y**2*(-b**2 - 8*b + 8))) + \
>          b**2*(b*(x**2 + y**2) + 2*x*y*(b - 2))**2
>
> Replace a,b with c,d (for `q_dp_2` and `s2`) to get `u2`. I can't imagine 
> that solving a pair of quartics is going to give a nice solution. But solving 
> this system with known values for `a` and `b` would be straightforward with 
> `nsolve`.
>
> /c
>
> On Thursday, August 4, 2022 at 11:54:24 PM UTC-5 [email protected] wrote:
>>
>> And eq1=Q_1*s_1 - Q_2*s_1 + 2*Q_2 - Q_dp_1 - 2*sqrt(Q_2*(Q_1*s_1 - Q_2*s_1 + 
>> Q_2 + 2*sqrt(Q_1*Q_2*s_1*(1 - s_1)))) + 2*sqrt(Q_1*Q_2*s_1*(1 - s_1)) ... 
>> sorry, long day!
>>
>> On Thursday, August 4, 2022 at 9:39:53 PM UTC-7 Kevin Pauba wrote:
>>>
>>> Sorry, Jeremy.  Good suggestion!
>>>
>>> s1, s2, q_dp1, q_dp2 = sym.symbols('s_1, s_2, Q_dp_1, Q_dp_2')
>>> eq1 = equ1.subs({ s: s1 }) - q_dp1
>>> md( "$" + sym.latex(eq1) + " = 0$\n" )
>>>
>>> eq2 = equ1.subs({ s: s2 }) - q_dp2
>>> md( "$" + sym.latex(eq2) + " = 0$\n" )
>>>
>>> soln = sym.solve([eq1, eq2], q1, q2)
>>> print(f"soln = {soln}")
>>>
>>> I'll set simplify to False and see how it goes ...
>>> On Thursday, August 4, 2022 at 8:18:00 PM UTC-7 Kevin Pauba wrote:
>>>>
>>>> I've attached a portion of a jupyter notebook.  I'm attempting to solve a 
>>>> simultaneous equation using sympy.  The sym.solve() in the green input box 
>>>> doesn't return (well, I waited over night on my macbook pro).  Might the 
>>>> solution be intractable?  Is there another way to get a solution?  Any 
>>>> help is greatly appreciated.
>
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