That would only work if the variable were an integer. If I remember
correctly, the variable type was unspecified. ;-)
- Brian
Chris Shiflett wrote:
Your first instinct, make a copy and then reassign the
values, is a straightforward way to do it.
I agree that using xor isn't a very straightforward solution, but I do
like to look for creative, clever solutions:
$foo = $foo + $bar;
$bar = $foo - $bar;
$foo = $foo - $bar;
By the way, I'm hiring. :-)
Chris
--
Thanks!
- Brian Dailey
Software Developer
New York, NY
www.dailytechnology.net
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