Sorry everybody it was a typing error when assembling the email. The "WHEN"
should have been "WHERE". I did use the "WHERE" when testing using MySQL
Monitor and the statement $sql = "SELECT access_code FROM authorised_users
(WHERE ) user_id = '$userid' AND user_password = '$password' AND account =
'$account'"; also had the missing WHERE in during testing but once again it was
a typing error when assembling the email.
Sorry about that.
----- Original Message -----
From: P. Ju (朱漢璇)
To: NYPHP Talk ; [EMAIL PROTECTED]
Sent: Friday, September 21, 2007 9:28 PM
Subject: Re: [nyphp-talk] MySQL Monitor V PHP & MySQL
Err, actually ignore the previous. However, where's your WHERE ?
$sql = "SELECT access_code
FROM authorised_users
user_id = '$userid' AND
user_password = '$password' AND
account = '$account'";
You're missing a "WHERE"
and in your MySQLMonitor statement, you typed WHEN. ??
I don't use that tool, but is that valid?
Patricia
On 9/21/07, PaulCheung <[EMAIL PROTECTED]> wrote:
I have researched, checked and tried everything I can think of and still
cannot get it to work.
when using MySQL monitor the following works
=================================
SELECT access_code FROM authorised_users WHEN
user_id = 'Nancy' AND
user_password = 'qwerty' AND
account = '48572998';
Access_code is displayed = 11966552
When using PHP & MySQL ($userid='Nancy', $user_password='qwerty',
$account='48572998')
====================
<?PHP session_start(); ob_start(); PHP?>
<HTML><HEAD><TITLE>auth</TITLE></HEAD>
<FORM action="X.php" id="primary" method="post">
<BODY>
<?PHP
$userid = $_POST['user'];
$password = $_POST['passcode'];
$account = $_POST['account'];
$self = $_SERVER['PHP_SELF'];
$referer = $_SERVER['HTTP_REFERER'];
$access_code = $access_code - $access_code;
/* FOR TEST ONLY */
echo ("user id = " . $userid . "<br>");
echo ("password = " . $password . "<br>");
echo ("account = " . $account . "<br>");
echo ("self = " . $self . "<br>");
/* VALIDATE FOR BLANK INPUT FIELD */
if( ( !$userid ) or ( !$password ) or (!$account) )
{ header( "Location:$referer" ); exit(); }
/*CONNECT TO MYSQL */
[EMAIL PROTECTED]( "localhost", "paul", "enter" )
or die( "Could not connect" );
/* CONNECT TO DATABASE */
$rs = @mysql_select_db( "test_db", $conn )
or die( "Could not select database" );
$rs = @mysql_select_db( "test_db", $conn ) or die( "Could not select
database" );
$sql = "SELECT access_code
FROM authorised_users
user_id = '$userid' AND
user_password = '$password' AND
account = '$account'";
$rs = mysql_query( $sql, $conn ) or die( "Could not execute query" );
$num = mysql_numrows( $rs );
if( $num != 0 )
{ $access_code = access_code;
echo ("testcheckpoint - Welcome - your log-in succeeded!" . "<br>");
echo ("testcheckpoint - accesscode = " . access_code . "<BR>");
echo ('testcheckpoint - $accesscode = ' . $access_code . "<BR>"); }
else
{ echo (" test checkpoint statement 55 " . "<br>");
header( "Location:$referer" );
exit(); }
===========================================
this is what is returned from the test
user id = Nancy
password = qwerty
account = 48572998
self = /tp_orth.php
conn = Resource id #2
sql = SELECT access_code FROM authorised_users WHERE user_id = 'Nancy' AND
user_password = 'qwerty' AND account = '48572998'
access = 0
Welcome - your log-in succeeded!
testcheckpoint - accesscode = access_code
testcheckpoint - $accesscode = access_code
I am trying to get the Access_code and cannot see what I am doing wrong
P
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--
Patricia Ju
[EMAIL PROTECTED]
+1-646-717-3871
success = f(perseverance) _______________________________________________
New York PHP Community Talk Mailing List
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http://www.nyphpcon.com
Show Your Participation in New York PHP
http://www.nyphp.org/show_participation.php
