Hi Ken,
The $access_code = $access_code - $access_code; is just an prehistoric
programming technique.
By the way the solution you proposed did not work; But the access_code is
now blank I would be most grateful for any other suggestions.
ser id = Nancy
password = qwerty
account = 48572998
self = /tp_orth.php
conn = Resource id #2
sql = SELECT access_code FROM authorised_users WHERE user_id = 'Nancy' AND
user_password = 'qwerty' AND account = '48572998'
Welcome - your log-in succeeded!
access_code =
$access_code =
Paul
----- Original Message -----
From: "Kenneth Dombrowski" <[EMAIL PROTECTED]>
To: <talk@lists.nyphp.org>
Sent: Friday, September 21, 2007 9:03 PM
Subject: Re: [nyphp-talk] MySQL Monitor V PHP & MySQL
Hi Paul,
On 07-09-21 20:47 +0100, PaulCheung wrote:
$access_code = $access_code - $access_code;
i don't understand what your intent is with the above line.. setting
$access_code to 0? (it's not your problem, i am just curious)
$rs = mysql_query( $sql, $conn ) or die( "Could not execute query" );
$num = mysql_numrows( $rs );
if( $num != 0 )
{ $access_code = access_code;
the above line looks to me like $access_code is being assigned the value
of the undefined constant access_code, which php will assume is intended
to be the string 'access_code'
i think you want $access_code = $rs['access_code']
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