Try emailing to get access rather than registering.
Registration for Download Please fill the <https://goo.gl/forms/6VwfnasNjkYm0Wqu2> Google Form for registration & license agreement. The password for downloading is emailed after registration. or please contact to the developer (yamadai [at] iis.u-tokyo.ac.jp) to get an access. From: Nuno Caldeira <[email protected]> Sent: Tuesday, 31 December 2019 5:50 AM To: Christoph Hormann <[email protected]> Cc: OpenStreetMap talk mailing list <[email protected]> Subject: Re: [OSM-talk] Licence of Facebook's derived road datasets? ODbL? here's a interested case https://www.gislounge.com/gis-data-high-resolution-global-hydrography-dataset/amp/ are they allowed to share this on CC4? Shouldn't it only be ODbL? are they allowed to share only after a registration? anyone wanna try getting a copy of the derivated work as they need to without registration? On Fri, Nov 15, 2019 at 4:20 PM Christoph Hormann <[email protected] <mailto:[email protected]> > wrote: On Friday 15 November 2019, Martin Koppenhoefer wrote: > > > there isn't OSM data in their dataset. > > > > And neither is there is my ocean data set - the OSM data set used > > only contains land masses, my resulting data set (D2 in Rory's > > terms) only contains oceans. So no OSM data in it. > > I doubt this cheap trick would pass when contested in a trial. Well - it is not my cheap trick, it is facebook's cheap trick. I am just following the lead here. There is no principal difference between what facebook does and what my scenario describes. > > If the question is not "addition or subtraction" consider the > > following scenario. You create a data set using some AI and big > > data process of 'potential restaurants' world wide and create a set > > intersection between those and the restuarants in OSM would the > > results be a derivative of OSM data? > > yes, if you look at the intersection (data in both sets), it would > be. If you took only what is not in OSM, I guess it wouldn't (no data > from OSM contained). So the set operation chosen (difference or intersection or any other) decides on the legal status of the resulting data set? You are aware that a difference is the same as an intersection with the complement, i.e. A \setminus B = A \cap B^c - see: https://en.wikipedia.org/wiki/Complement_(set_theory) -- Christoph Hormann http://www.imagico.de/ _______________________________________________ talk mailing list [email protected] <mailto:[email protected]> https://lists.openstreetmap.org/listinfo/talk
_______________________________________________ talk mailing list [email protected] https://lists.openstreetmap.org/listinfo/talk

