On 18/07/2012 14:04, David Carlisle wrote:
for is just an expression
true
so you could for example use
false sorry, you can't use concat here, the verions below using
string-join are OK though.
concat($hdr,for $i in ......)
of course in this simple example you don't need the variable at all as
$hdr is already just a call to concat you could return the single
expression
concat('Id', codepoints-to-string(9), 'Name',
codepoints-to-string(10),
for $i in$doc/item return
concat($i/id, codepoints-to-string(9), $i/name, codepoints-to-string(10)
)
or more simply
string-join(
('Id	Name',$doc/item/concat(id,'	',name)),' ')
the let and for clauses aren't really needed,
David
--
google plus: https:/profiles.google.com/d.p.carlisle
________________________________________________________________________
The Numerical Algorithms Group Ltd is a company registered in England
and Wales with company number 1249803. The registered office is:
Wilkinson House, Jordan Hill Road, Oxford OX2 8DR, United Kingdom.
This e-mail has been scanned for all viruses by Star. The service is
powered by MessageLabs.
________________________________________________________________________
_______________________________________________
[email protected]
http://x-query.com/mailman/listinfo/talk