I think for the purposes of this, you must take 0 as even. And
starting at zero gives exactly the same result as 2,4,6,8 - you get
101
213
123

With the number 1:
011
213
123

On 4/29/05, Abinanthan.B <[EMAIL PROTECTED]> wrote:
>  
>  
> 
> IS 0 A EVEN NUMBER? 
> 
>   
> 
> WHAT IF I TAKE THE STRATING NUMBER ITSELF AS "0"? 
> 
>   
>  
>  ________________________________
>  
> 
> From: [email protected] [mailto:[EMAIL PROTECTED] On Behalf
> Of vijay gopinath
>  Sent: 29 April 2005 12:39
>  To: [email protected]
>  Subject: RE: [tech4all] MATHEMATICAL BLACK HOLE 
>  
> 
>   
>  
> 
> 222 ----- 
>  
> 
> No: of even numbers - 3 
>  
> 
> No: 0f Odd numbers - 0 
>  
> 
> Total number - 3 
>  
> 
> Therefore 303 -----That leads to again 
>  
> 
> No of even Numbers -1 
>  
> 
> No of odd numbers -2 
>  
> 
> Total number - 3 
>  
> 
> Therefore "123 " 
>  
> 
>   
>  
> 
> Same with 4 too 
>  
> 
>   
>  
> 
> Thanks , 
>  
> 
>   
>  
> 
> Vijay
>  
>  "Abinanthan.B" <[EMAIL PROTECTED]> wrote: 
>  
> 
> what about 222 or 4?
>  
>  -----Original Message-----
>  From: [email protected]
>  To: [email protected]; [EMAIL PROTECTED];
>  [EMAIL PROTECTED]
>  Sent: 28/04/2005 15:36
>  Subject: [tech4all] MATHEMATICAL BLACK HOLE
>  
>  Whhhhattt? Black hole in maths?
>  Yup.. In maths a black hole is a number to which an
>  operation on any of the elements of UNIVERSAL set
>  finally leads to... figuratively speaking everything
>  "BOILS DOWN TO THAT ELEMENT.."
>  
>  The following are two of the mathematical BLACK
>  HOLES...
>  
>  The Sisyphus String: 123
>  
>  Suppose we start with any natural number, regarded as
>  a string, such as 9288759. Count the number of even
>  digits, the number of odd digits, and the total number
>  of digits. These are 3 (three evens), 4 (four odds),
>  and 7 (total of seven digits). So, use these digits to
>  form the next string or number, 347.
>  
>  Now repeat with 347, counting evens, odds, total
>  number, to get 1, 2, 3, so write down 123. If we
>  repeat with 123, we get 123 again. The number 123 with
>  respect to this process and universe of numbers is a
>  mathemagical black hole. All numbers in this universe
>  are drawn to 123 by this process, never to escape.
>  
>  Will every number really be sent to 123? Try
>  
>  122333444455555666666777777788888888999999999.
>  
>  The numbers of evens, odds, and total are 20, 25, and
>  45, respectively. So, our next iterate is 202545, the
>  number obtained from 20, 25, 45. Iterating for 202545
>  we find 4, 2, and 6 for evens, odds, total, so we have
>  426 now. One more iteration using 426 produces 303,
>  and a final iteration from 303 produces 123.
>  
>  Narcissistic Numbers: 153
>  
>  It is well known that, other than the trivial examples
>  of 0 and 1, the only natural numbers that equal the
>  sum of the cubes of their digits are 153, 370, 371,
>  and 407. Of these, only 153 has a black-hole property.
>  To create a black hole, we need to define a universe
>  (set U) and a process (function f). We start with any
>  positive whole number that is a multiple of 3. Recall
>  that there is a shortcut to test whether you have a
>  multiple of 3. Just add up the digits and see whether
>  that sum is a multiple of 3. For instance, 111111 (six
>  ones) is a multiple of 3 because the sum of the
>  digits, 6, is. However, 1111111 (seven ones) is not.
>  Since we are going to be doing some arithmetic, you
>  may wish to take out a hand-calculator and/ or some
>  paper. Write down your multiple of 3. One at a time,
>  take the cube of each digit. Add up the cubes to form
>  a new number. Now repeat the process. You must
>  eventually reach 153. Moreover, once you reach 153,
>  another iteration just gets you 153 again.
>  
>  Let's test just one initial instance. Using the sum of
>  the cubes of the digits, if we start with 432 - a
>  multiple of 3 - we get 99, which leads to 1458, then
>  702, which yields 351, finally leading to 153, at
>  which point, future iterations keep producing 153.
>  Note also that this operation or process preserves
>  divisibility by 3 in the successive numbers.
>  
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