RMS X 1.414 = PEAK
RMS X 2.828 = PEAK TO PEAK
PEAK X 0.707 = RMS
P-P X 0.3535 = RMS
Chuck Perlingiero
Chuck's Electronic Repair
(610) 623-2224
(610) 259-9618 (Fax)
[EMAIL PROTECTED]


-----Original Message-----
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] Behalf Of Mark Wentowski
Sent: Tuesday, May 04, 2004 11:28 PM
To: ELECTRONICS PROFESSIONALS LIST
Subject: RE: [Techs] Need advice from engineering folks.

No Walter. You are talking DC. I need a quick refresher on AC. .404 X peak
=RMS? I just can't remember. Bob Waterman is the expert. Perhaps he will see
this and help out.

AC theory is tough. It's not like re-wiring your mama's lamp.

Mark Wentowski
Perry Hill Electronics
3836 Harrison Rd.
Montgomery AL 36109
phone: (334)279-5622
fax:   (334)273-9050
[EMAIL PROTECTED]

-----Original Message-----
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] Behalf Of walter wood
Sent: Tuesday, May 04, 2004 9:00 PM
To: Techs
Subject: [Techs] Need advice from engineering folks.




> Watts divided volts equal amps.
> 100 watts divided by 100 volts = 1 amp.
> That's the way a broadcast engineer told me to
> remember Ohms Law 40 years ago.
> Now the reason for the question;
> I have provided the main outdoor sound system,
> gratis, for the last 3 years, for the Relay for
> Life charity.
> The local college provides the lights, and the
> electric company puts a tempoary service at the
> location.
> We've never had enough electricity.
> Thet are offering to put a permanent service
> there,
> and want to know how much IS enough.
> I measured the current through a 100 watt light
> bulb, on normal line voltage and read 0.82 amps.
> That's about right as the voltage was up from the
> example, therefore the amperage goes down.
> I measured a 60 watt bulb and got 0.5, exactly
> what
> it should be.
> I then measured a Peavey Session 400 amp, and it
> read 0.44 amps at idle, but it didn't take much
> volume to raise the draw to 1 amp.
> The back plate on this amp states 600 watts and
> 120
> volts.
> It is fused at 6 amps.
> Following the formula, it should pull 5 amps
> "maxed
> out".
> I know that's a lot of e-mail, but the question
> can
> be answered yes or know.
> "Will I be safe in requiring the amperage of all
> the amps and effects, etc. to equal the total of
> their fused ratings."
> I would think that would be more than adaquite,
> but
> I'm asking for the expert advice.
> I intend to ask for much more because we see the
> need getting larger in the future, and anyway,
> it's
> impossible to know what kind of equipment
> everyone
> will show up with.
> The college already knows the requirments for the
> lights.
> TIA
> Water




=====
Walter Wood
Future Tech Home Center
2786 Hwy. 43 N.
Lawrenceburg Tn. 38464
931-829-3337
Fax 931-829-4044
mailto:[EMAIL PROTECTED]




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