Sergey Martynoff wrote:
But what about support for backslash-escaped '$' sign in replace string? It seems to be achieved quite easily, changind the line where actual replace takes place:$matched =~ s/\$$i/$backref/g;with this: $matched =~ s/(?<!\\)\$$i(?!\d)/$backref/g; This also solves probles with "unused" backreferences, when you use something like replace("(this)","that$10") ending up with "that0" instead of desired "that".
I saw this in Paul's code as well. I think it's a pretty good idea, but there is one thing to point out. It gives the user the impression that escaping is valid in replacement.
For example if the string is '\\$3' what then? Do we escape the backslash. This could be a slippery slope, but for now I'm fine with saying '\$' and '\\$' are both invalid for backrefs for now.
Given that '$' is used quite a bit for money, I think it's probably a good thing to allow escaping.
-- Josh _______________________________________________ templates mailing list [email protected] http://lists.template-toolkit.org/mailman/listinfo/templates
