Andre wrote

> I known
> that Don (always) is right ...

I appreciate the thought, but I disagree with it. But if I'm not always
right, maybe I'm wrong about this, and maybe therefore I really am always
right. And I know a barber who shaves everyone in town except himself.

Here's one argument why 4 notes in 3 quarters should have no flags: If you
had three notes in three quarters, like the first bar in Andre's example,
each one has length 1.0 quarters and 0 flags. If you had 3 notes in 2
quarters, like the 7th bar in Andre's example, each one has length 0.667
quarters and 0 flags. With 4 notes in three quarters, each note has length
0.75 quarters. That's BETWEEN the lengths of notes in two cases where no one
(except maybe Andre's friends) would argue that there should be no flags.

In case anyone is interested, the formula that PMX uses to compute the
number of flags in an xtuplet is

INT(13.429+(0.952*LN(nnotes)-LN(32*wholes))/0.69315)-10

where "wholes" is the fractional number of whole notes duration for the
entire xtuplet, and nnotes is the number of notes. I derived this formula
myself. If anyone wants to know why it doesn't depend directly on
wholes/nnotes (the length of each individual note), I'll have to get back to
you because I don't remember exactly, but I think I have a record somewhere.

--Don

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