Thanks Mark,

I'll try this. I'm going a few steps back to get a few steps forward here.

Could you provide a link the the 'hash compact method' ?

ALex

2009/11/25 Mark S. <[email protected]>

> Thought about using the hash compact method the other day ... can't
> remember why I didn't pursue it.
>
> Anyways, you're not using the object generated by the funtion. Try
> changing this:
>
>  eliminateDuplicates(arrToClean);
>  out.push(clean);
>
> to this:
>
>  out = eliminateDuplicates(arrToClean);
>
> Mark
>
> On Nov 25, 3:51 am, Alex Hough <[email protected]> wrote:
> > I've found a way to eliminate duplicates from an array [1] and applied it
> to
> > my code. I am not familiar enough with functions to know why it does not
> > work, but think that it is a simple solution.
> >
> > the script is below
> >
> > Alex
> >
> > [1]
> http://stackoverflow.com/questions/840781/easiest-way-to-find-duplica...
> >
> > <script>
> >
> > function eliminateDuplicates(arr) {
> >   var i,
> >       len=arr.length,
> >       clean=[],
> >       obj={};
> >
> >   for (i=0;i<len;i++) {
> >     obj[arr[i]]=0;
> >   }
> >   for (i in obj) {
> >     clean.push(i);
> >   }
> >   return clean;
> >
> > }
> >
> > var arrToClean=[];
> > var out=[];
> > tids=['Q1','Q2','Q3','Q4','Q5','Q6'];
> > for (var i=0; i<tids.length; i++) {
> >         var t=tids[i].title;
> >     var score=DataTiddler.getData(tids[i],"score");
> >     var val=store.getValue(tids[i],"primary");
> >     var val1=store.getValue(tids[i],"secondary");
> >     var filter="[tag["+val.readBracketedList().join("]][tag[")+"]]";
> >     var filter1="[tag["+val1.readBracketedList().join("]][tag[")+"]]";
> >     var
> >
> list=store.filterTiddlers(filter).map(function(t){return"[["+t.title+"]]"});
> >     var
> >
> list1=store.filterTiddlers(filter1).map(function(t){return"[["+t.title+"]]"});
> >
> > arrToClean.push(list.concat(list1));
> >
> > }
> >
> > eliminateDuplicates (arrToClean);
> > out.push(clean);
> > return out.join("\n");
> > </script>
>
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