Hi Bill: It's my understanding that a satellite is in free fall, hence zero g.
Of course there's a gravitational field at the location of the satellite, the one from Earth being the largest. Orbital mechanics gives me a headache so let's hear from someone more knowledgeable. Have Fun, Brooke Clarke, N6GCE http://www.PRC68.com http://www.precisionclock.com WB6BNQ wrote: > Brooke Clarke wrote: > > >>Gravity also effects atomic clocks, see: http://www.leapsecond.com/great2005/ >>and this puts a limit on what can be done with any atomic clock that's on >>Earth. "g" will always have minor fluctuations (noise) due to all sorts of >>things like the Sun, Moon, planets, asteroids, earthquakes, etc. It's still a >>direct "g" effect called red shift like (U2 − U1)/c2, where the Us are >>gravitational potentials, only smaller by c squared. > > > If all of the above affects the gravitational action on the surface of the > Earth, > then how is the statement, below, true ? > > >>I expect that in not too many years the official master clocks will no longer >>be on Earth, but instead in satellites. There "g" is precisely known to be >>zero. Since GPS satellites are excellent for time transfer that's where they >>will be. The ensemble will be the full constellation. > > > It would seem that the satellite, which is just an arms throw from the > surface, > would have the same affects acting upon it, albeit perhaps in modified ways. > I > would think the satellite would have to be placed at the center of the SUN to > have > all of the effects (within our solar system) reduced to the smallest amount. > > Can anyone elaborate on this ? Thanks, > > Bill......WB6BNQ > > > > _______________________________________________ > time-nuts mailing list > [email protected] > https://www.febo.com/cgi-bin/mailman/listinfo/time-nuts > _______________________________________________ time-nuts mailing list [email protected] https://www.febo.com/cgi-bin/mailman/listinfo/time-nuts
