El 22/10/2011 15:13, Jim Lux escribió:

Two things spring to mind:

Spectrum analyzers don't have very low noise inputs, in general. Did you account for the additional noise from that source?

The noise bandwidth is not necessarily the same as the resolution bandwidth (the shape of the filter isn't rectangular, after all). You'd have to look at the phase noise measuring ap notes from HP, I think they give the correction factor to use (it's more than a dB, as I recall)

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Thanks, Jim. Yes, I've accounted it, the noise source is around 20dB over the analyzer noise, so analyzer noise can be neglected. I was missing the correction due to the filter form factor, and thanks, Sylvain, for pointing me to the application note, that shows this correction and other more important (in dB terms) due to the log detection and averaging process of the video filter, so I must add 2.51dB, and substract 0.51dB due to the filter shape, so I must correct add 2dB. I see that the shift-M function already provides this correction (I was missing that! Thanks!)

I've make sure that no analyzer compression or overloading is taking place. Also, the bandwidth of the noise source is limited to approx. 1.2GHz, centered at 8.2GHz, so the analyzer does not see too much noise power (around -15dBm total noise power). I've checked changing the attenuation values from 0, 10 and 20dB and the analyzer noise floor varies as expected, but the noise source measurement does not change.

I was missing also to add a 1.2dB for the analyzer cable loss, and after playing a bit around, the value I get at the center frequency is -102dBm/Hz, around 8dB higher that I was expecting, but probably the measurement is ok and the fixed losses due to the other elements were somewhat overestimated during the design, and the gain of the amplifier that is in the noise path is a bit higher than expected. I will measure directly at the noise source output, and check losses and amplifier gain, but to have a bit more of noise available is not a problem in this case (in fact, it is an advantage). Mainly I was looking to be sure that I was measuring it in the right way, so thank you very much for your help.

Best regards,

Javier, EA1CRB

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