Moin, On Sat, 29 Oct 2011 19:12:39 +0000 "Poul-Henning Kamp" <[email protected]> wrote:
> In message <[email protected]>, Attila Kinali writes: > > >Is it because they can be aproximated as single electron > >systems due to the one electron in the valence orbit? > > Yes. Basically that electron is in a "figure of eight" orbital > which means that it passes straight through, or possibly just > very close by, the proton, allowing their spin moments to interact. I guess you mean here the exited state, when the electron is in a p-orbital? For the ground state s-orbital (ball shaped), the electron's density function should have a zero at the nucleus for all but the 1s orbital, if i'm not mistaken. And wouldn't that be the case with non-alkali metals too? If it's about the shape of the orbital, then Bor should work as fine, if not better, as the ground state of the "top most" electron is a p-orbital, which means it would have longer time to interact with the nucleus. > I belive K has been tried. I've not seen it mentioned anywhere and a google search didn't provide anything. > I belive the preference for H, Rb & Cs is that getting them as > single atoms doesn't require high temperatures. That might explain it. Attila Kinali -- Why does it take years to find the answers to the questions one should have asked long ago? _______________________________________________ time-nuts mailing list -- [email protected] To unsubscribe, go to https://www.febo.com/cgi-bin/mailman/listinfo/time-nuts and follow the instructions there.
