>> If I want to decode a GPS signal, do I have to know (or figure out) the >> frequency of the local oscillator? Or does it drop out of the calculations, >> somehow?
> Yes, it comes out in the calculations. > That's why you need 4 satellites. You solve for x,y,z and local clock > offset. (and, in reality you also have to solve for xdot,ydot,zdot, and > fdot) Thanks. I thought the 4th satellite was needed to determine the time. Wouldn't it take a 5th satellite to also determine the frequency of the local clock? -- These are my opinions, not necessarily my employer's. I hate spam. _______________________________________________ time-nuts mailing list -- time-nuts@febo.com To unsubscribe, go to https://www.febo.com/cgi-bin/mailman/listinfo/time-nuts and follow the instructions there.
