Yes, [] can be applied to any pointer. But, it is an operator, like "+".
So, a[i], is an operation involving a and i. In fact, it IS the operation +. a[i] is *(a + i) Now *(a + i) is the same as *(i + a). And thus, a[i] is the same as i[a]. Now, a is the same as a pointer, so we can write i[p]. And, we know that the constant 0 is a pointer, so we can have i[0]. Which means that (eg.) 5[0] and 0[5] may be valid constructs (but, they have "void" type, so the de-reference should fail!). Hope that helps, Fred. _______________________________________________ Tinycc-devel mailing list [email protected] http://lists.nongnu.org/mailman/listinfo/tinycc-devel
