On Wed, Nov 14, 2007 at 12:39:18AM +0100, grischka wrote:
> > Could a C guru out there please tell me why the following works?
> > Extra points if you can explain why it makes sense.
> >
> > #include <stdio.h>
> >
> > int main(){
> > int arr[10];
> > printf("%d\n",sizeof arr[0]); // ok
> > printf("%d\n",sizeof(arr[0])); // ok
> > printf("%d\n",sizeof(arr)[0]); // ok, but why?
> > return 0;
> > }
>
> And what about that one:
>
> printf("%d\n",sizeof (0)[arr]);
Yep even stranger. The good thing is that if you add another pair of
parantheses tcc takes it and life is good.
printf("%d\n",sizeof((arr)[0]));
printf("%d\n",sizeof((0)[arr]));
I think your problem is the syntax of a[b] and the sizeof operator.
int a;
sizeof a == sizeof (a) == sizeof (int)
int *v;
v[5] == *(v+5) == *(5+v) == 5[v] last but not least insert parenthesis:
((v)[(5)])
ok?
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