Hi all,
I'm thinking that my programming logic might be wrong which is why the
compiler gave me this warning:
XxxxC.nc: In function `Receive.receive':
XxxxC.nc:117: warning: passing argument 2 of `AMSend.send' from incompatible
pointer type
I read through the Receive interface and was told that if I wanted to
return the same message_t packet buffer for later use by the same signalling
component, I can do so provided I have copied the data that I wanted. In my
program, I wanted selected nodes with certain IDs to modify the data that
they received from another node and send it to another different node -
hence, in my Receive.receive(message_t* bufPtr, void* payload, uint8_t len),
I signalled AMSend.send after I have modified the data... This was what I
did:
message_t* tempBuffer;
struct* something = (struct*)payload;
something->data = something->value + count - something->data
memcpy(tempBuffer, bufPtr, sizeof(message_t));
call AMSend.send(nodeid, &tempBuffer, sizeof(struct));
return bufPtr;
I'm not really sure if this will actually send the modified data to the
required nodeid, but anyway, I still don't know why the message appears.
I'm not even sure if I need tempBuffer in the first place - can I just send
&bufPtr? Any help is very much appreciated. Thank you.
Azhar
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