Yes, it's because you are using a multimeter. With a 1 ohm resistor, you will be reading about .02 volts difference. You should read the voltage across the resistor, not measure on both sides and take the difference. Most multimeters do some autoscaling.
You may have more success using the ammeter function if the only instrument you have is a multimeter. We have one of the better Fluke hand held multimeters, and it measures the on current fairly well, but the current when the mote is sleeping is way off. Eric On Thu, May 29, 2008 at 9:27 PM, Shomnat Mitra <[EMAIL PROTECTED]> wrote: > Hello , > > I have gone through several help archives to find a way to measure the > current draw of the motes. > > All suggest using a 1 ohm resistor in series with the + ve terminal of the > battery and the other end of the resistor attached to the PCB, > and measuring the voltage across this resistor. > > The readings are 1.5V which is the battery voltage. > I have tried several positions on the mote to attach the resistor, but none > show any change. > > The reading also doesn't show any change when I use HPLPowerManagement in my > programs. > > Is it because i am using a Multimeter ? > > Can anybody suggest the exact way to do this ? > > Thanks in advance , > Somnath > > _______________________________________________ > Tinyos-help mailing list > [email protected] > https://www.millennium.berkeley.edu/cgi-bin/mailman/listinfo/tinyos-help > _______________________________________________ Tinyos-help mailing list [email protected] https://www.millennium.berkeley.edu/cgi-bin/mailman/listinfo/tinyos-help
