Hi Annette 

Perhaps McNemar's Test for significance of changes, for dichotomous data. For 
each item, set up a table that looks like a 2*2 chi square but has "pretest" 
and "post-test" as variables (in texts its usually labelled "before" and 
"after") . 
Posttest 
- + 
+ A B 
Pretest 
- C D 

So every S appears as one count in the table and A+B+C+D = total N. But the key 
cells are A and D. Since (A+D) equals the people who changed, we expect half of 
(A+D) in A and D if the Null is true. The frequency expected for both A and D 
is (A+D)/2 ... Then you just do a chi square on those two cells. The formula 
simplifies to 

chi square = (A - D)squared / (A + D) with df = 1. 

The Wikipedia link is http://en.wikipedia.org/wiki/McNemar%27s_test, and I just 
noticed it reorders the rows and columns so that B and C are the "change" 
variables. It also reminds us about Yates correction .. Unfortunately, I don't 
use SPSS much these days so I don't know how to find it or code the variables 
for the chi square! Not sure about the chance issue. The p values may be all 
you need ,.. but you may want a correction for chance?? Others will know more 
.... 




========================== 
John W. Kulig, Ph.D. 
Professor of Psychology 
Coordinator, University Honors 
Plymouth State University 
Plymouth NH 03264 
========================== 

----- Original Message -----

From: "Annette Taylor" <[email protected]> 
To: "Teaching in the Psychological Sciences (TIPS)" 
<[email protected]> 
Sent: Tuesday, January 15, 2013 6:21:42 PM 
Subject: [tips] my crummy knowledge of stats 

I know this is a basic question but here goes: 

I have categorical data, 0,1 which stands for incorrect (0) or correct (1) on a 
test item. 

I have 25 items and I have a pretest and a posttest and I want to know on which 
items students improved significantly, and not just by chance. Just eyeballing 
the data I can tell that there are some on which the improved quite a bit, some 
not at all and some are someplace in the middle and I can't make a guess at 
all. That is why we have statistics. Yeah! .... hmmmm....bleh..... 

As far as I know, the best thing to do is a chi-square test for each of 25 
items; but of course that will mean that with a .05 sig level I will have at 
least one false positive, maybe more, but most assuredly at least one. This 
seems to be a risk. At any rate I can use SPSS and the crosstabs command allow 
for calculation of the chi-square. 

I know that when I do planned comparisons with multiple t-tests, I can do a 
Simes' correction in which I can rank order my final, obtained alphas, and 
adjust for the number of comparisons and reject from the point from which the 
obtained alpha failed to exceed the corrected-for-number-of-comps alpha. But as 
far as I know, I cannot do that with 25 chi square tests. There is probably 
some reason why I can no more do that, that relates to the reason for why I 
cannot do 25 t-tests in this situation with categorical data. 

Is there a better way to answer my research question? I need a major professor! 
Oh wait, that's me... drat! I need to hire a statistician. Oh wait, I'd need $$ 
for that and I don't have any. So I hope tipsters can stand in as a 
quasi-hired-statistician and help me out. 

Oh, I get the digest. I don't mind waiting until tomorrow or the next day for a 
response, but a backchannel is fine. [email protected] 

I will be at APS this year. Any other tipsters planning to be there? Let's have 
a party! I'd love to put personalities to names. 

Thanks 

Annette 

Annette Kujawski Taylor, Ph. D. 
Professor, Psychological Sciences 
University of San Diego 
5998 Alcala Park 
San Diego, CA 92110 
[email protected] 
--- 
You are currently subscribed to tips as: [email protected]. 
To unsubscribe click here: 
http://fsulist.frostburg.edu/u?id=13338.f659d005276678c0696b7f6beda66454&n=T&l=tips&o=23044
 
or send a blank email to 
leave-23044-13338.f659d005276678c0696b7f6beda66...@fsulist.frostburg.edu 


---
You are currently subscribed to tips as: [email protected].
To unsubscribe click here: 
http://fsulist.frostburg.edu/u?id=13090.68da6e6e5325aa33287ff385b70df5d5&n=T&l=tips&o=23065
or send a blank email to 
leave-23065-13090.68da6e6e5325aa33287ff385b70df...@fsulist.frostburg.edu

Reply via email to