As soon as you do anything involving t or F (like test a hypothesis or 
construct a confidence interval), there is a normality assumption.  As Stuart 
notes, computing the r requires no distribution assumptions.  Of course the 
same is true of the mean.  Then again, r is really just a special mean.

Cheers,

Karl W.
-----Original Message-----
From: Stuart McKelvie [mailto:smcke...@ubishops.ca] 
Sent: Monday, November 11, 2013 1:47 PM
To: Teaching in the Psychological Sciences (TIPS)
Subject: RE: [tips] What to do with skewed data

Dear Tipsters,

Although the Pearson coefficient does not assume normality, an alternative 
solution might be to computer a non-parametric coefficient such as Spearman's 
rho or Kendall's tau.

Sincerely,

Stuart

______________________________
"Recti Cultus Pectora Roborant"

Stuart J. McKelvie, Ph.D.,
Department of Psychology,
Bishop's University,
2600 rue College,
Sherbrooke (Borough of Lennoxville),
QC J1M 1Z7,
Canada.

"Floreat Labore"
______________________________


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