Dear all,
I would like to ask how to get the web virtual path
of a specified project in tomcat.
E.g. I got a project APPLE which are placed all
source in /webapp/APPLE.
By default, this project can be accessed by
Http://localhost:8080/APPLE/
Assume I am running a servlet called 'EAT.class' ,
then the path should be something like that
Http://localhost:8080/APPLE/servlet/EAT .
How can EAT.class know this path when running INIT()
function ?
I know that we can get some parameters from web.xml
by using getInitParameter() function. I also know that
we can get the virtual path by using
request.getRequestURI() inside doPost()/doGet()
function. But I don't know how to get it inside INIT()
function.
Thank you for your help!
M.T.
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