Dear Craig,
Is that the servlet instance will be created once a
request is coming in ? The target class will call
init() when it is called at first time ?
My whole picture is :
request -> target class -> init()
Thx.
M.T.
--- "Craig R. McClanahan" <[EMAIL PROTECTED]> wrote:
> Unfortunately, there is no means within the init()
> method of a servlet to
> determine the context path of this web application
> (i.e. the
> '/APPLE" part of a complete request URI). You won't
> know that until the
> first request comes in.
>
> Craig McClanahan
>
>
> On Mon, 6 Aug 2001, Diu Lee Lo Mo wrote:
>
> >
> > Dear all,
> >
> > I would like to ask how to get the web virtual
> path
> > of a specified project in tomcat.
> >
> > E.g. I got a project APPLE which are placed all
> > source in /webapp/APPLE.
> >
> > By default, this project can be accessed by
> > Http://localhost:8080/APPLE/
> >
> > Assume I am running a servlet called 'EAT.class'
> ,
> > then the path should be something like that
> > Http://localhost:8080/APPLE/servlet/EAT .
> >
> > How can EAT.class know this path when running
> INIT()
> > function ?
> >
> > I know that we can get some parameters from
> web.xml
> > by using getInitParameter() function. I also know
> that
> > we can get the virtual path by using
> > request.getRequestURI() inside doPost()/doGet()
> > function. But I don't know how to get it inside
> INIT()
> > function.
> >
> > Thank you for your help!
> >
> > M.T.
> >
>
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