Just a quick testing tip:

You don't have to disconnect the AC right at the peak.  If the circuitry   
downstream from the line-to-line cap can handle DC, then use a DC power   
supply to charge the capacitor up to the same voltage as the peak of your   
AC supply voltage (e.g. 1.414 x 120Vac = 170Vdc).  This avoids the tricky   
business of managing to disconnect right at the peak of an AC waveform.

Regards,

Jim Eichner
Statpower Technologies Corp.
Burnaby, B.C., Canada
[email protected]
Any opinions expressed are those of my invisible friend, who really   
exists.  Honest.
    


 -----Original Message-----
From: jppena@anetMHS (Juan Pedro Pe?a){MHS:[email protected]}
Sent: Thursday, October 23, 1997 5:07 AM
To: emc-pstc@anetMHS (EMC-PSTC){MHS:[email protected]}; JEichner;   
bceresne
Subject: RE: Capacitor discharge: IEC950 2.1.10

   

Many other standards state that voltage shall decay under a safety level
(i.e., 60 V). However, to measure it is necessary to cut the power just
in the top of the wave, and it is difficult. If we speak about
percentage, that problem won't exist: the decay time until 37% of it
initial value depends only on the time constant of the circuit,
independently of the initial voltage.

But you are right and that definition may force an excessive
requirement. Maybe,  the best option could be to mix both methods.

Juan P. Pena  / Electrical Safety Area
Company: CETECOM, S.A. (http://www.cetecom.es)
e-mail: [email protected]


 ----------
 De:  Munechika Gomi[SMTP:[email protected]]
 Enviado el:  viernes 3 de octubre de 1997 8:35
 Para:  EMC-PSTC
 Asunto:  Capacitor discharge: IEC950 2.1.10

 Would anyone tell me why IEC950 allows a capacitor having a
discharge means
 in a time constant not exceeding: ---, i.e. during one
time-constant the
 voltage decays to 37 % of its original value?

 The reason of my question is:

 If the original voltage is 120 V ac, 37 % or its original will
exceed 60 V
 dc which I think is hazardous in terms of voltage.

 Is there any implied consideration in IEC950 for energy level
other than
 voltage?

 Thank you for your help in advance.

 Mike Gomi

Reply via email to