On Wed, 12 Jan 2005 [EMAIL PROTECTED] wrote: > Quoting Bill Kranec <[EMAIL PROTECTED]>: > > > I have a list of lists, for example [ [1,2] , [3,4] ], and I would like > > to pass all the elements of that list as arguments to a function (for > > example the intersection of all list elements). Is there a command in > > regular Python to do this? I would like to avoid the hassle and speed > > hit of a loop to extract all the list elements. > > I don't think so... > > There is a recipe on activestate for a flatten function. > > Or you could use a list comprehension: > > >>> arr = zip(range(10), range(10, 20)) > >>> arr > [(0, 10), (1, 11), (2, 12), (3, 13), (4, 14), (5, 15), (6, 16), (7, 17), (8, > 18), (9, 19)] > >>> [x for y in arr for x in y] > [0, 10, 1, 11, 2, 12, 3, 13, 4, 14, 5, 15, 6, 16, 7, 17, 8, 18, 9, 19] >
Nice. And there's: >>> arr = zip(range(10), range(10, 20)) >>> arr [(0, 10), (1, 11), (2, 12), (3, 13), (4, 14), (5, 15), (6, 16), (7, 17), (8, 18), (9, 19)] >>> reduce(lambda x,y:x+y, arr) (0, 10, 1, 11, 2, 12, 3, 13, 4, 14, 5, 15, 6, 16, 7, 17, 8, 18, 9, 19) >>> > -- _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
