Hi John,
you can use 'pass' . This works the same as with exceptions, eg
try:
open('somefile')
except IOError:
pass
so we can have
class doNothing:
def __init__(self):
pass
def boring(self, other):
pass
Hope that helps :)
Nick
-----Original Message-----
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
Behalf Of Gooch, John
Sent: 26 May 2005 16:43
To: tutor@python.org
Subject: [Tutor] Are Empty "Placeholder" Functions possible?
Is there a way to create an empty function definition with no lines of code
in it? In my coding style I will often do this ( in other languages ) for
RAD just to remind myself that I will need to implement the function later.
Example: For a file handling class, I may need functions such as
copy,delete,move,etc so I want to start off with:
class FileHandler:
def __init__(self):
def copy(self):
def delete(self):
.
.
.
then in my driver/aka testing file:
import FileHandler
def main()
MyHandler = FileHandler()
print "Handler Created."
main()
Right now, this won't work as the compliler will error on functions with
nothing in them. Is there a "no-op", "do nothing", or some similar command I
can put in the empty functions to keep the compiler/interpreter from
erroring on them? This would really help speed up my development so that I
can create the class skeleton quickly and then implement each function and
test it as I go.
Thank You,
John A. Gooch
Systems Administrator
IT - Tools
EchoStar Satellite L.L.C.
9601 S. Meridian Blvd.
Englewood, CO 80112
Desk: 720-514-5708
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