On 17/11/06, Dave S <[EMAIL PROTECTED]> wrote:
> Hi,
>
> I have a bunch of lists within lists that I need to sort ref item [4], I can't
> access my code at the moment but I basically ...
>
[...]
>
> Having googled I think there is a better way of doing this with the key
> attribute
>
> a.sort(key= ?? )
Yep, that's right. You need at least python2.4 for this, though.
You need to pass the key= parameter a function that will take an
element of your list, and return the comparison key.
eg:
def item4(elem):
return elem[4]
a.sort(key=item4)
Since this is a common thing to do, there is a function in the
operator module that you can use, instead of defining your own:
import operator
a.sort(key=operator.itemgetter(4))
(operator.itemgetter(4) will return a function that is basically
equivalent to item4() above)
HTH!
--
John.
_______________________________________________
Tutor maillist - [email protected]
http://mail.python.org/mailman/listinfo/tutor
