The most concise way to do this is to transpose the list (convert a axb array to bxa), then complare the elements that are pairs of one value each of the original lists.
You have two lists, a and b. Put these into a list and you have a 2x6 2d "array". >>> [a,b] [[4, 3, 2, 6, 7, 9], [8, 6, 3, 3, 2, 7]] A quick way to do a transposition is to use the built-in zip() function. This doesn't do error checking! If you need to do this in production code, you need to check that the lists are of even lengths. zip() will truncate the lists until they are all teh same size! >>> zip(*[a,b]) [(4, 8), (3, 6), (2, 3), (6, 3), (7, 2), (9, 7)] So, to get a list of booleans, you can do this: >>> [x>y for x,y in zip(*[a,b])] [False, False, False, True, True, True] Cheers On Tuesday 25 December 2007 09:00, sith . wrote: > Hi, > I've read the posts on comparing 2 lists and couldn't find the answer to my > question. I have 2 lists > a = [4,3,2,6,7,9] > b = [8,6,3,3,2,7] > How can I determine if the elements in a are larger or smaller than the > elements in b. > > for i in a: > for u in b: > i > u > does not return the result I seek. > > In this example, 4 from a is compared to 8,6,3,3,2,7 then 3 from a is > compared to all the elements in b. I'd like > 4 to 8, > 3 to 6, > 2 to 3 and so on; like 2 columns in excel, the third column would be a new > list of boolean values. Can someone help please? Thank you. > > > --------------------------------- > Never miss a thing. Make Yahoo your homepage. _______________________________________________ Tutor maillist - [email protected] http://mail.python.org/mailman/listinfo/tutor
