Hi, a = [4,3,2,6,7,9] b = [8,6,3,3,2,7]
You can turn this into a list of two element tuples with zip(): >>> zip(a,b) [ (4,8),(3,6,),(2,3),(6,3),(7,2),(9,7) ] Now you can loop through that and compare both elements, for instance I believe this list comprehension is what you're looking for: [ t[0] < t[1] for t in zip(a,b) ] but of course we can write that more elegantly with [ i<j for i,j in zip(a,b) ] Gives a list of booleans. Remco Gerlich On Dec 25, 2007 4:52 PM, sith . <[EMAIL PROTECTED]> wrote: > sith . wrote: > > Hi, > > I've read the posts on comparing 2 lists and couldn't find the answer to > > my question. > > I have 2 lists > > a = [4,3,2,6,7,9] > > b = [8,6,3,3,2,7] > > How can I determine if the elements in a are larger or smaller than the > > elements in b. > > > > for i in a: > > for u in b: > > i > u > > does not return the result I seek. > > > > In this example, 4 from a is compared to 8,6,3,3,2,7 then 3 from a is > > compared to all the elements in b. > > I'd like > > 4 to 8, > > 3 to 6, > > 2 to 3 and so on; like 2 columns in excel, the third column would be a > > new list of boolean values. > > Can someone help please? Thank you. > > > all(all(i>j for j in b) for i in a) > HTH > > > Hi, > Thanks for your reply. This is what I get: > >>> a = [4,3,2,6,7,9] > >>> b = [8,6,3,3,2,7] > >>> all(all(i>j for j in b) for i in a) > >>> all(all(i>j for j in b) for i in a) > False > How do I make it loop through the whole list? > > ------------------------------ > Never miss a thing. Make Yahoo your > homepage.<http://us.rd.yahoo.com/evt=51438/*http://www.yahoo.com/r/hs> > > _______________________________________________ > Tutor maillist - Tutor@python.org > http://mail.python.org/mailman/listinfo/tutor > >
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