Well, this assumes that all named attributes do exist. If not, you need to replace x.attr with getattr(x, "attr", defaultvalue) ;)
l.sort(key=lambda x: (x.content_type, x.submit_date))
Now, you can construct a sorted list "t":
t = []
for key, item_iterator in itertools.groupby(l, key=lambda x: (x.content_type,
x.submit_date)):
sorted_part = sorted(item_iterator, key=lambda x: x.submit_date)
t.append((sorted_part[-1].submit_date, key, sorted_part))
t.sort()
t = sum([x[2] for x in t], [])
Totally untested, as written in the MTA :)
Andreas
Am Montag, den 03.03.2008, 22:19 +0800 schrieb Eric Abrahamsen:
> I have a grisly little sorting problem to which I've hacked together a
> solution, but I'm hoping someone here might have a better suggestion.
>
> I have a list of objects, each of which has two attributes, object_id
> and submit_date. What I want is to sort them by content_type, then by
> submit_date within content_type, and then sort each content_type block
> according to which block has the newest object by submit_date. (This
> sequence of sorting might not be optimal, I'm not sure). I'm actually
> creating a list of recent comments on blog entries for a python-based
> web framework, and want to arrange the comments according to blog
> entry (content_type), by submit_date within that entry, with the
> entries with the newest comments showing up on top.
>
> I don't believe a single cmp function fed to list.sort() can do this,
> because you can't know how two objects should be compared until you
> know all the values for all the objects. I'd be happy to be proven
> wrong here.
>
> After some false starts with dictionaries, here's what I've got.
> Queryset is the original list of comments (I'm doing this in django),
> and it returns a list of lists, though I might flatten it afterwards.
> It works, but it's ghastly unreadable and if there were a more
> graceful solution I'd feel better about life in general:
>
>
> def make_com_list(queryset):
> ids = set([com.object_id for com in queryset])
> xlist = [[com for com in queryset if com.object_id == i] for i in
> ids]
> for ls in xlist:
> ls.sort(key=lambda x: x.submit_date)
> xlist.sort(key=lambda x: max([com.submit_date for com in x]),
> reverse=True)
> return xlist
>
> I'd appreciate any hints!
>
> Thanks,
> Eric
> _______________________________________________
> Tutor maillist - Tutor@python.org
> http://mail.python.org/mailman/listinfo/tutor
signature.asc
Description: Dies ist ein digital signierter Nachrichtenteil
_______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
