Here is a version based on Andreas' solution using groupby() that avoids the decorate-undecorate by using the key= parameter for the second sort:
l.sort(key=lambda x: (x.content_type, x.submit_date)) t = [ list(items) for key, items in itertools.groupby(l, key=lambda x: (x.content_type)) ] t.sort(key=lambda x: x[-1].submit_date, x[-1].object_id) Kent _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
