Hi,
I made a very simple program to send everybody I know a change of address I am
parsing the .msg files with another function, which returns a set called
'recipients'.
The code below works, but it displays all recipients in the 'to' field. That
is, in the Nth iteration, N recipients are shown. So the first mail has one
recipient in the 'to' field, the second mail has the first and the second
recipient, and so forth. I only want one recipient to be shown in the 'to'
field.
Pointers, anyone?
Thanks!
Albert-Jan
import smtplib, email.utils
from email.mime.text import MIMEText
msg = MIMEText("""Dear reader:\n\nblaaaaah blaah blaah.\nSincerely,\nThe
dude""")
sender = 'r...@stimpy.com'
recipients = ['happyha...@joy.com', 'y...@eediot.com]
for no, recipient in enumerate(recipients):
print "--> Sending message to: %s (%s of %s)" % (recipient, no+1,
len(recipients))
msg['To'] = email.utils.formataddr((recipient, recipient))
print msg['To']
msg['From'] = email.utils.formataddr(('Cool dude', sender))
msg['Subject'] = 'Change of email address'
server = smtplib.SMTP("mysmtpserver.isp.com")
server.set_debuglevel(True)
try:
server.sendmail(sender, [recipient], msg.as_string())
finally:
server.quit()
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