On Mon, Jun 8, 2009 at 1:42 PM, Albert-jan Roskam <fo...@yahoo.com> wrote:
>
> Hi,
>
> I made a very simple program to send everybody I know a change of address I
> am parsing the .msg files with another function, which returns a set called
> 'recipients'.
>
> The code below works, but it displays all recipients in the 'to' field.
> That is, in the Nth iteration, N recipients are shown. So the first mail has
> one recipient in the 'to' field, the second mail has the first and the
> second recipient, and so forth. I only want one recipient to be shown in the
> 'to' field.
So your code would, in this case, print out
"happyha...@joy.com" <happyha...@joy.com>
"y...@eediot.com" <y...@eediot.com>
or does it print out
"happyha...@joy.com" <happyha...@joy.com>
"happyha...@joy.com" <happyha...@joy.com>
"y...@eediot.com" <y...@eediot.com>
If it's the former, that's what you have told it to do.
If it's the latter, I'm not sure what the problem is, unless it has
something to do with your debug level.
HTH,
Wayne
>
>
> Pointers, anyone?
>
> Thanks!
> Albert-Jan
>
> import smtplib, email.utils
> from email.mime.text import MIMEText
>
> msg = MIMEText("""Dear reader:\n\nblaaaaah blaah blaah.\nSincerely,\nThe
> dude""")
>
> sender = 'r...@stimpy.com'
> recipients = ['happyha...@joy.com', 'y...@eediot.com]
> for no, recipient in enumerate(recipients):
> print "--> Sending message to: %s (%s of %s)" % (recipient, no+1,
> len(recipients))
> msg['To'] = email.utils.formataddr((recipient, recipient))
> print msg['To']
> msg['From'] = email.utils.formataddr(('Cool dude', sender))
> msg['Subject'] = 'Change of email address'
>
> server = smtplib.SMTP("mysmtpserver.isp.com")
> server.set_debuglevel(True)
> try:
> server.sendmail(sender, [recipient], msg.as_string())
> finally:
> server.quit()
>
>
>
>
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