Hugo Arts, 13.01.2010 15:25:
Here is my solution for the general case:from itertools import groupby def alphanum_key(string): t = [] for isdigit, group in groupby(string, str.isdigit): group = ''.join(group) t.append(int(group) if isdigit else group) return t
Note that this won't work in Py3, where integers and strings are not ordered, i.e. not comparable w.r.t the < and > operators.
Stefan _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
