On 09/22/2011 10:27 AM, Joel Knoll wrote:
Seems like the easiest way would be to duplicate the range once (so you have a list twice as long), and then use various slices of it.Given a range of integers (1,n), how might I go about printing them in the following patterns: 1 2 3 4 ... n2 3 4 5 ... n 13 4 5 6 ... n 1 2 etc., e.g. for a "magic square". So that for the range (1,5) for example I would get 1 2 3 42 3 4 13 4 1 24 1 2 3 I just cannot figure out how to make the sequence "start over" within a row, i.e. to go from 4 down to 1 in this example. I have been grappling with this problem for 2.5 days and have gotten nowhere!_______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
x = list(range(1, 5)) #could omit the list() function in python 2.x x2 = x+x for the nth row, use row = x2[n:n+n] -- DaveA
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