forgot to forward to list: From: Hugo Arts <hugo.yo...@gmail.com> Date: Thu, Sep 22, 2011 at 4:42 PM Subject: Re: [Tutor] range question To: d...@davea.name
On Thu, Sep 22, 2011 at 4:37 PM, Dave Angel <d...@davea.name> wrote: > On 09/22/2011 10:27 AM, Joel Knoll wrote: > > Given a range of integers (1,n), how might I go about printing them in the > following patterns: > 1 2 3 4 ... n2 3 4 5 ... n 13 4 5 6 ... n 1 2 > etc., e.g. for a "magic square". So that for the range (1,5) for example I > would get > 1 2 3 42 3 4 13 4 1 24 1 2 3 > I just cannot figure out how to make the sequence "start over" within a row, > i.e. to go from 4 down to 1 in this example. > I have been grappling with this problem for 2.5 days and have gotten > nowhere! > > _______________________________________________ > Tutor maillist - Tutor@python.org > To unsubscribe or change subscription options: > http://mail.python.org/mailman/listinfo/tutor > > Seems like the easiest way would be to duplicate the range once (so you have > a list twice as long), and then use various slices of it. > > x = list(range(1, 5)) #could omit the list() function in python 2.x > x2 = x+x > > for the nth row, use > row = x2[n:n+n] > Surely you meant to type: x = list(range(1, 6)) x2 = x + x row = x[n:n+len(x)] _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
