On Sun, Aug 26, 2012 at 4:36 PM, eryksun <eryk...@gmail.com> wrote: > > it's 0. Once it's 0, a new pizza is created to be dropped. The > designer wants a 30% buffer (in steps) between the time one pizza has > finished dropping and the creation of a new pizza.
To clarify, say the chef is at y=100, and a pizza is 100 pixels high with a speed of 2 pixels/step. check_drop() creates a new pizza and sets time_til_drop to 1 + int(100 * 1.3 / 2) = 66. So check_drop will be called 66 times, i.e. (65, 64, ..., 0), before another pizza gets created. In that time the previous pizza has fallen 2 * 66 = 132 pixels, from y=100 down to y=232 (if 0,0 is the upper left-hand corner). The bottom of the next pizza is at y = 100 + 100 = 200. That leaves a buffer between them of 232 - 200 = 32 pixels, which is 32% in this case. _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
