Hello Hugo, # Defines the start of a function and its options (question) def question_y_n(question):
#1. Ask Question from user, user enters either Yes, No or whatever (anything that is not Yes or No) answer = input(question) # prompts the user and assigns the answer to var answer #2. If the user had entered anything but Yes then a while loop starts and becomes True (meaning it is not a Yes) so it must be either No or something else while(answer != "Yes"): #3. If the answer is anything but a No then the user is prompted with statement and then the question asked again if answer != "No": #4. Print statement and ask question again. print("Please enter Yes or No for your response!") answer = input(question) #5. It is assumed that if the answer was not a Yes in the while loop and it was not a No in the if statement than it is assumed the only other choice would be a No for the else statement. else: answer = "No" break return answer answer = question_y_n("You want a drink of water? :") print("Your answer to the question was ", answer) This code works and produces the results that I am looking for, however I know there is a better way to do it and now you have me thinking about this again. I just spent about 3 hours doing this code. I was thinking of combining the Yes and No into one check however I was having trouble finding resource of how to do mulitiy checks in a statement for while. thinking like this: def question_y_n(question): answer = input(question) while(answer != "Yes" Or "No"): #This is wrong code print("Please enter Yes or No for your response!") answer = input(question) or # This one does not have ability to loop intill a Yes or No is given so my gut tells me the one above is better or the one I have at this time. def question_y_n(question): answer = input(question) if answer == "Yes" OR "No": #this didn't work either for me break else print("Please enter Yes or No for your response!") answer = input(question) return answer Sorry for this layout, I myself was getting a little dizzy reading it. Thank you for your assistance! Sincerely in Christ, Christopher _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor