On 03/15/2013 06:09 PM, Christopher Emery wrote:
------ Hugo said:
----
----1. ask a question, receive an answer
----2. if the answer is "Yes" or "No", return the answer
----3. else, print a message and go back to step 1
Hello Hugo,
# Defines the start of a function and its options (question)
def question_y_n(question):
#1. Ask Question from user, user enters either Yes, No or whatever
(anything that is not Yes or No)
answer = input(question) # prompts the user and assigns the answer
to var answer
#2. If the user had entered anything but Yes then a while loop starts
and becomes True (meaning it is not a Yes) so it must be either No or
something else
while(answer != "Yes"):
Hugo's function description is perfectly symmetric with regard to Yes &
No. But you've changed that, both in your new description, and in your
code. Why is the "while" checking only for "Yes" when it should be
checking for either/both?
<SNIP>
I was thinking of combining the Yes and No into one check however I
was having trouble finding resource of how to do mulitiy checks in a
statement for while.
thinking like this:
def question_y_n(question):
answer = input(question)
while(answer != "Yes" Or "No"): #This is wrong code
print("Please enter Yes or No for your response!")
answer = input(question)
or
Do you understand about compound if/while expressions? You can combine
boolean expressions with 'and' and 'or' .
For example, if you had wanted to check for either 4 or 12, you might do
something like:
if myint == 4 or myint == 12:
do something
else:
do something else
--
DaveA
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