Hi Leam,
On 3 April 2014 15:24, leam hall <leamh...@gmail.com> wrote:
>
> I've been trying to so a simple "run a command and put the output into a
> variable". Using Python 2.4 and 2.6 with no option to move. The go is to do
> something like this:
>
> my_var = "ls -l my_file"
>
> So far the best I've seen is:
>
> line = os.popen('ls -l my_file', stdout=subprocess.PIPE, shell=True)
> (out, err) = line.communicate()
>
> With no way to make 'my_file' a variable.
If you use IPython, this can be as simple as the following (this is on
windows, so 'ls -l' has been replaced by 'dir'):
Python 2.7.5 (default, May 15 2013, 22:43:36) [MSC v.1500 32 bit (Intel)]
Type "copyright", "credits" or "license" for more information.
IPython 1.0.0 -- An enhanced Interactive Python.
? -> Introduction and overview of IPython's features.
%quickref -> Quick reference.
help -> Python's own help system.
object? -> Details about 'object', use 'object??' for extra details.
In [1]: my_file='virtualenv.exe'
In [2]: my_var=!dir {my_file}
In [3]: print my_var
[' Volume in drive C has no label.', ' Volume Serial Number is
E8D7-900D', '', ' Directory of C:\\Python27\\Scripts', '', '2011/06/24
11:12 7\xff168 virtualenv.exe', ' 1 File(s)
7\xff168 bytes', ' 0 Dir(s)
47\xff655\xff469\xff056 bytes free']
In [4]:
Walter
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