On 03/04/14 14:24, leam hall wrote:
I've been trying to so a simple "run a command and put the output into a
variable". Using Python 2.4 and 2.6 with no option to move. The go is to
do something like this:
my_var = "ls -l my_file"
I'm not sure what you mean here?
What should my_var contain? The command string or the result of the
command? In this case that would be a long file listing including all
the access, size info etc?
So far the best I've seen is:
line = os.popen('ls -l my_file', stdout=subprocess.PIPE, shell=True)
(out, err) = line.communicate()
Don't use os.popen(), it should be viewed as legacy code.
Use subprocess instead. There are several options including the call()
function, or the full blown Popen class.
With no way to make 'my_file' a variable.
In your original version you could use string formatting to insert the
file name but using subprocess the issue goes away because you build the
command as a list of substrings, one of which is the file(in your case)
and it can be a variable or literal as you require.
I've got to be missing something, but I'm not sure what. Python has
always impressed me a a language without a lot of hoops to go through.
subprocess can be a tad daunting but it is very powerful and once you
get the hang of it quite straightforward.
HTH
--
Alan G
Author of the Learn to Program web site
http://www.alan-g.me.uk/
http://www.flickr.com/photos/alangauldphotos
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