Screenname and password. Your @username, not your email address.

-John


On Thu, Sep 9, 2010 at 6:56 AM, omri <[email protected]> wrote:

> this is the message i get :
>
>  File &quot;C:\Python26\lib\urllib2.py&quot;, line 516, in
> http_error_default
>    raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
> HTTPError: HTTP Error 401: Unauthorized
>
> i think i dont know which username and password to type in the header
> - 'Authorization' 'basic (username:password)
> the twitter's username?
> the twitter api oauth?
>
> thanks
>
>
> On 9 ספטמבר, 15:42, John Kalucki <[email protected]> wrote:
> > What text message does it return with the 401 error?
> >
> > You can still use basic auth with streaming. Does that work for you? You
> > should use your screenname and password for basic auth.
> >
> > -John Kaluckihttp://twitter.com/jkalucki
> > Twitter, Inc.
> >
> >
> >
> > On Thu, Sep 9, 2010 at 2:48 AM, omri <[email protected]> wrote:
> > > hi,
> > > now it returns the 401 error.
> > > It seems like I don't know what is the username and password i should
> > > insert.
> >
> > > is this ths oauth token?
> > > what is the title of this fields?
> >
> > > API key, Consumer key, Consumer secret?
> >
> > > thanks
> >
> > > On 7 ספטמבר, 17:16, John Kalucki <[email protected]> wrote:
> > > > The Streaming API will print a short text message along with errors
> that
> > > is
> > > > often a very explicit indication of the problem. I don't think it
> throws
> > > 500
> > > > errors (see:
> http://dev.twitter.com/pages/streaming_api_response_codes)
> > > so
> > > > something odd is going on. If anything, it is throwing a 406, as you
> > > haven't
> > > > provided parameters to track.
> >
> > > > -John Kaluckihttp://twitter.com/jkalucki
> > > > Twitter, Inc.
> >
> > > > On Tue, Sep 7, 2010 at 4:38 AM, omri <[email protected]> wrote:
> > > > > def run (self):
> > > > >    status_url = "http://stream.twitter.com/1/statuses/filter.json";
> > > > >    request = urllib2.Request(status_url)
> > > > >    print request
> > > > >    auth = base64.encodestring('Consumer key:Consumer secret')[:-1]
> > > > >    request.add_header('Authorization', 'basic %s' % auth)
> > > > >    firehose = urllib2.urlopen(request)
> > > > >    for tweet in firehose:
> > > > >        print tweet
> >
> > > > >    firehose.close
> >
> > > > > when printing the request i have  500 error, it is not reachable.
> >
> > > > > do you have an idea why?
> >
> > > > > --
> > > > > Twitter developer documentation and resources:
> > >http://dev.twitter.com/doc
> > > > > API updates via Twitter:http://twitter.com/twitterapi
> > > > > Issues/Enhancements Tracker:
> > > > >http://code.google.com/p/twitter-api/issues/list
> > > > > Change your membership to this group:
> > > > >http://groups.google.com/group/twitter-development-talk?hl=en
> >
> > > --
> > > Twitter developer documentation and resources:
> http://dev.twitter.com/doc
> > > API updates via Twitter:http://twitter.com/twitterapi
> > > Issues/Enhancements Tracker:
> > >http://code.google.com/p/twitter-api/issues/list
> > > Change your membership to this group:
> > >http://groups.google.com/group/twitter-development-talk?hl=en
>
> --
> Twitter developer documentation and resources: http://dev.twitter.com/doc
> API updates via Twitter: http://twitter.com/twitterapi
> Issues/Enhancements Tracker:
> http://code.google.com/p/twitter-api/issues/list
> Change your membership to this group:
> http://groups.google.com/group/twitter-development-talk?hl=en
>

-- 
Twitter developer documentation and resources: http://dev.twitter.com/doc
API updates via Twitter: http://twitter.com/twitterapi
Issues/Enhancements Tracker: http://code.google.com/p/twitter-api/issues/list
Change your membership to this group: 
http://groups.google.com/group/twitter-development-talk?hl=en

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