Here's how I do it... JJ = ICONV(THE.DATE, 'D') MO = OCONV(JJ, 'DM') YR= OCONV(JJ, 'DY') DAY=28 LOOP TRY = OCONV(ICONV(MO:'/':DAY+1:'/':YR, 'D'), 'DM') WHILE TRY = MO DO REPEAT LAST.DAY = MO:'/':DAY:'/':YR
Perry Taylor -----Original Message----- From: Marco Manyevere [mailto:[EMAIL PROTECTED] Sent: Thu Jun 02 14:05:42 2005 To: u2-users@listserver.u2ug.org Subject: [U2] Finding last day of month Hi, Given a date like 20040203, I want to return the last valid date for that month and year (20040229 in this case). What is the shortest code fragment to achieve this? At the moment I'm replacing the day with 01, then iconv, add 35 days to the internal date and then oconv and replace the day again with 01. I'm then on the first day of the next month. I then iconv, subtract 1 day and oconv. Thanks for any help. --------------------------------- Yahoo! Messenger NEW - crystal clear PC to PCcalling worldwide with voicemail ------- u2-users mailing list u2-users@listserver.u2ug.org To unsubscribe please visit http://listserver.u2ug.org/ CONFIDENTIALITY NOTICE: This e-mail message, including any attachments, is for the sole use of the intended recipient(s) and may contain confidential and privileged information. Any unauthorized review, use, disclosure or distribution is prohibited. ZirMed, Inc. has strict policies regarding the content of e-mail communications, specifically Protected Health Information, any communications containing such material will be returned to the originating party with such advisement noted. If you are not the intended recipient, please contact the sender by reply e-mail and destroy all copies of the original message. ------- u2-users mailing list u2-users@listserver.u2ug.org To unsubscribe please visit http://listserver.u2ug.org/
