Hmmm... That leads to an interesting idea. If you consider a space to be
'something', then test.1 is really the only 'empty' array, and the following
would work, without doing any trims or conversions:
IF SUM(SUM(NES(TEST.x,REUSE('')))) THEN (string is not empty)
You could also make it work, considering spaces to be empty by amending it
thusly:
IF SUM(SUM(NES(CONVERT(' ','',TEST.x),REUSE('')))) THEN (string is not
empty)
Remember: eschew obfuscation ;-)
Larry Hiscock
Western Computer Services
-----Original Message-----
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of john reid
Sent: Wednesday, February 01, 2006 10:39 AM
To: [email protected]
Subject: Re: [U2] Is a dynamic array "empty" or not?
Me too, 'cause TEST.2 isnt empty I dont think. Unless blanks are not
'something'
I always use EQS or NES functions for evaluation. Just make an array
using the same delimiters, and say
TEST.3 = @VM:@AM:' ':@VM:'zzz':@VM:@AM:'abc':@AM
TEST.1 = @VM:@AM:@VM:@VM:@AM:@AM
TEST.2 = @VM:@AM:' ':@VM:' ':@VM:@AM:' ':@AM
XYZ=EQS(TEST.1,TEST.3)
CRT XYZ
1}1~0}0}1~0~1
OR...
am I missing something?
j
On 2/1/06, Wendy Smoak <[EMAIL PROTECTED]> wrote:
> I'm probably missing something obvious here...
> What can I use to evaluate the "emptiness" of these arrays, so that 1
> and 2 are considered empty and 3 is not?
>
> TEST.1 = @VM:@AM:@VM:@VM:@AM:@AM
> TEST.2 = @VM:@AM:' ':@VM:' ':@VM:@AM:' ':@AM
> TEST.3 = @VM:@AM:' ':@VM:'zzz':@VM:@AM:'abc':@AM
>
> Thanks!
> Wendy Smoak
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--
john
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