# Re: [UD] 8 Bite Integers

```Fawaz,

>I have a Unidata numeric field
>(Amount- 100.00 or -100.00) and I need to convert it
>to a 8 Bite integer so that Informix will recognise
>it.```
```
Do you mean 8bit or 8byte?

For an 8 bit integer you need to output CHAR(n) where n is a number between
0 and 255.

For an 8 byte (64 bit) integer you would need to do something like this. I
aplogise if this isn't correct UD code, I usually work on UV. I am assuming
that the output integer is in MSB order and that the bits of each byte are
in MSb order.

ININT = 1145689
GOSUB MAKE8BYTE

STOP

MAKE8BYTE:
* Initialise output as 0
OUTINT = STR(CHAR(0), 8)

FOR I = 1 TO 8
* Get lowest 8bits
LOWESTBYTE = BITAND(ININT, 255)
* Convert this to a byte representation and place it in the output
integer
OUTINT[8-I, 1] = CHAR(LOWESTBYTE)
* Remove the lowest byte 8bits from the integer
ININT = INT(ININT/256)
NEXT I
RETURN

HTH,

Craig

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```