In this case, we're counting delimiters - not items, so it I'm sure
it should be the number of items -1, unless we have a trailing
delimiter, when the item count and delimiter count are the same,
hence the need for "& null" or testing the last char.
This is how it seems to work on my setup (rev 2.7, Mac OS X):
1,2,3 = 3 items, 2 delimiters
,1,2,3 = 4 items (one empty), 3 delimiters
1,2,3, = 3 items, 3 delimiters - Rev doesn't count the implied empy
item at the end.
Cheers,
Mark
On 1 Mar 2006, at 20:12, Jim Ault wrote:
Also, shouldn't the count be
'the number of items in textStr -1?
As I indicated in a previous post, it depends on what you are
trying to
count when you use items a measure.
If the last char of a string is the asciiChar, then the number of
items will
be one less than the true count, however, if null is appended, the
count
will be equal to the true count.
_______________________________________________
use-revolution mailing list
[email protected]
Please visit this url to subscribe, unsubscribe and manage your subscription
preferences:
http://lists.runrev.com/mailman/listinfo/use-revolution
