you can extend the formats and set the delimiter that way. https://commons.apache.org/proper/commons-csv/archives/1.2/apidocs/org/apache/commons/csv/CSVFormat.html
https://commons.apache.org/proper/commons-csv/archives/1.2/apidocs/org/apache/commons/csv/CSVFormat.html#withDelimiter-char- On Wed, Aug 9, 2017 at 12:51 PM, nitin mahendru <nitin.mahendr...@gmail.com> wrote: > Hi Gary, > > Thanks for a quick turnaround. We are using the below code to parse our > input csv: > CSVFormat.RFC4180.withIgnoreEmptyLines(true).parse(new > InputStreamReader(this.getStreamIn(), readerCharset)) > > We never tell the parser what line separator to expect and it automatically > figures it out. What I want to know is that is it possible to extract this > knowledge from the CSVParser object returned by the above as to what line > separator it found ? > > -Nitin > > > On Tue, Aug 8, 2017 at 3:23 PM Gary Gregory <garydgreg...@gmail.com> > wrote: > > > Hi Nitin, > > > > You _tell_ the parser what record separator to use, the parser does not > > tell you. > > > > Gary > > > > > > On Aug 8, 2017 16:13, "nitin mahendru" <nitin.mahendr...@gmail.com> > wrote: > > > > Hello All, > > > > I am trying to read in a csv file which may be 'crlf' or 'lf' seperated. > > Then I want to change a particular column, say encrypt it and then write > > back a new csv with that updated column. I want to use the same record > > separator as was in the input file. > > > > Is there a way to get the record separator back from the CSVParser > object ? > > I am planning to use the below method to get the writer. > > CSVFormat.RFC4180.withRecordSeparator(<need to add record > > separator).print() > > > > For using the above I need to know the record separator upfront which I > > have no clue about as the Parser object does not expose that detail. > > > > thanks > > > > Nitin > > >
