Thanks Vangeli, So let me get this straight. Can I write:
<dir:directory xmlns:dir="http://apache.org/cocoon/directory/2.0"; name="the/dir/" sort="name" reverse="false"> <dir:file name="*.xml"> <dir:xpath query="*"/> </dir:file> </dir:directory> to get all the contents of all files in the/directory? (I'm sorry but I'm ignorant about xpath) Then the question is how do I put this in a forrest's aggregation. Or I don't need an aggregation if I use this? --Vassilis On 3/3/07, Evangelos Vlachogiannis <[EMAIL PROTECTED]> wrote:
Hi Vasili, I think you need Xpathdirectory Generator (http://cocoon.apache.org/2.1/userdocs/xpathdirectory-generator.html). I hope this is included in forrest.. Then you just have a root element (elements) and call an xpath expression to include what ever elements you need from xmls in dir. hope that helps, Vangelis Vassilis Koutavas wrote: > What is the right way to create one aggregated xml file from all the > xml files in a directory? > I think I need to use map:aggregate, map:part, and dir:directory in my > sitemap.xml, but I don't quite understand how to put them together. I > don't know how many files will be in the directory, thus I don't know > how many parts the aggregation will have. > > Let's say that in my xdocs I have the directory called "the/dir/" in > which there are a number of xml files, and I want to create a file > called "the-list.xml" (in the same direcory) which will contain the > contents of all the xml files in that directory, under a common > element called "elements". After I have this I know how to transform > it using an xsl, and produce the final html file. > > Best -- --------------------------------------------------------------- Evangelos Vlachogiannis Researcher - PhD. Candidate Contact: http://www.syros.aegean.gr/users/evlach/contactme.php ---------------------------------------------------------------
-- Vassilis
