Hi Vasili,
lets say you have n xml files in a dir with root elements
<article></article>
<map:generate type="xpathdirectory" src="the/requested/directory">
<map:parameter name="xpath" value="/article"/>
<map:parameter name="xmlFiles" value="\.x.*$"/>
</map:generate>
this will return something like:
<dir:directory xmlns:dir="http://apache.org/cocoon/directory/2.0";
name="articles" lastModified="1057183738609" date="03.07.03 00:08" size="0"
requested="true" sort="name" reverse="false">
<dir:file name="article1.xml" lastModified="1057183738609" date="03.07.03 00:08"
size="123">
<dir:xpath query="/article">
<article>My first article - whole xml!</article>
</dir:xpath>
</dir:file>
<dir:file name="article2.xml" lastModified="1057183738609" date="03.07.03 00:08"
size="123">
<dir:xpath query="/article">
<article>My second article - whole xml!</article>
</dir:xpath>
</dir:file>
</dir:directory>
Then you can play with 1 or more xslt files and get the serialization
you need.
But remember you need to check if this generator is included in
forrest... I do not know... I have used that with cocoon, no with
forrest...
Vangelis
Vassilis Koutavas wrote:
Thanks Vangeli,
So let me get this straight. Can I write:
<dir:directory xmlns:dir="http://apache.org/cocoon/directory/2.0";
name="the/dir/" sort="name" reverse="false">
<dir:file name="*.xml">
<dir:xpath query="*"/>
</dir:file>
</dir:directory>
to get all the contents of all files in the/directory? (I'm sorry but
I'm ignorant about xpath)
Then the question is how do I put this in a forrest's aggregation. Or
I don't need an aggregation if I use this?
--Vassilis
On 3/3/07, Evangelos Vlachogiannis <[EMAIL PROTECTED]> wrote:
Hi Vasili,
I think you need Xpathdirectory Generator
(http://cocoon.apache.org/2.1/userdocs/xpathdirectory-generator.html). I
hope this is included in forrest..
Then you just have a root element (elements) and call an xpath
expression to include what ever elements you need from xmls in dir.
hope that helps,
Vangelis
Vassilis Koutavas wrote:
> What is the right way to create one aggregated xml file from all the
> xml files in a directory?
> I think I need to use map:aggregate, map:part, and dir:directory in my
> sitemap.xml, but I don't quite understand how to put them together. I
> don't know how many files will be in the directory, thus I don't know
> how many parts the aggregation will have.
>
> Let's say that in my xdocs I have the directory called "the/dir/" in
> which there are a number of xml files, and I want to create a file
> called "the-list.xml" (in the same direcory) which will contain the
> contents of all the xml files in that directory, under a common
> element called "elements". After I have this I know how to transform
> it using an xsl, and produce the final html file.
>
> Best
--
---------------------------------------------------------------
Evangelos Vlachogiannis
Researcher - PhD. Candidate
Contact: http://www.syros.aegean.gr/users/evlach/contactme.php
---------------------------------------------------------------
--
---------------------------------------------------------------
Evangelos Vlachogiannis
Researcher - PhD. Candidate
Contact: http://www.syros.aegean.gr/users/evlach/contactme.php
---------------------------------------------------------------
